New start day 1: 30/09/2020 codeforces (4A) Watermelon

 Question: source (codeforces:https://codeforces.com/problemset/problem/4/A)

Watermelon

One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that, the watermelon was weighed, and the scales showed w kilos. They rushed home, dying of thirst, and decided to divide the berry, however they faced a hard problem.

Pete and Billy are great fans of even numbers, that's why they want to divide the watermelon in such a way that each of the two parts weighs even the number of kilos, at the same time the parts don't need to be equal. The boys are extremely tired and want to start their meal as soon as possible, that's why you should help them and find out if they can divide the watermelon in the way they want. For sure, each of them should get a part of a positive weight.

Input

The first (and the only) input line contains integer number w (1 ≤ w ≤ 100) — the weight of the watermelon bought by the boys.

Output

Print YES, if the boys can divide the watermelon into two parts, each of them weighing an even number of kilos; and NO in the opposite case.

Examples
input
8
output
YES
Note

For example, the boys can divide the watermelon into two parts of 2 and 6 kilos respectively (another variant — two parts of 4 and 4 kilos).


my logic:

the question is a simple number theory question. A Sum of two evens can never be odd so if the given weight  w is an odd number then it cannot be divided into two even numbers. 2 is the only exception to this rule

for example, if the input is 8 we can divide it into pairs of (2,6), (4,4) but with 9 as the input
we can't find any such pair.

My Code:



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